2) z = [m]\frac{t^2}{t^2 - u^2}[/m] Найти! [m]\frac{dz}{du}[/m]
dz/du=z`_(u)=t^2*((t^2-u^2)^(-1))`_(u)=t^2*(-1)*((t^2-u^2)^(-2)) * (t^2-u^2)`_(u)= [m]=\frac{t^2}{(t^2-u^2)^2}\cdot (0-2u)=\frac{2ut^2}{(t^2-u^2)^2}[/m]