2) z = [m]\frac{t^2}{t^2 - u^2}[/m] Найти! [m]\frac{dz}{du}[/m]
dz/du=z`u=t2·((t2–u2)–1)`u=t2·(–1)·((t2–u2)–2) · (t2–u2)`u= [m]=\frac{t^2}{(t^2-u^2)^2}\cdot (0-2u)=\frac{2ut^2}{(t^2-u^2)^2}[/m]