По частям u=5x-2 dv=2^(x)dx du=5dx v=2^(x)/ln2 [m]=\frac{(5x-2)2^{x}}{ln2}-\int \frac{2^{x}}{ln2}5dx=\frac{(5x-2)2^{x}}{ln2}-\frac{5}{ln2}\cdot\frac{2^{x}}{ln2}+C[/m]