[m]x\overset{f}{\rightarrow}\frac{x^2-1}{x^2}[/m]
поэтому сложная функция f(g(x)):
[m]x\overset{g}{\rightarrow}\frac{1}{x^2}\overset{f}{\rightarrow}\frac{(\frac{1}{x^2})^2-1}{(\frac{1}{x^2})^2}[/m]
f(g(x))=[m]\frac{(\frac{1}{x^2})^2-1}{(\frac{1}{x^2})^2}[/m]
f(g(x))=[m]\frac{\frac{1}{x^4}-1}{\frac{1}{x^4}}[/m]
f(g(x))=1-x^4
f(g(x))=1-2^4=1-16=[b]-15[/b]