Задача 43275 ...

vk223915990

2020-01-08 15:32:20

∫ e^x dx/e^x +1

sova

2020-01-08 16:30:18

e^(x)+1=[blue]u[/blue]

[green]du[/green]=u`*dx=(e^(x)+1)`dx=(e^(x)+0)dx=[green]e^(x)dx[/green]


∫ [green]e^(x) dx[/green]/([blue]e^(x) +1[/blue])= ∫ [green]du[/green]/[blue]u[/blue]=ln|[blue]u[/blue]|+C=ln|e^(x)+1|+C