Задача 42750 ...

sova

2019-12-16 22:03:40

★

[m]\frac{2^{x}\cdot 2^{-y}}{3^{x}cdot 3^{-y}}=\frac{24}{81}[/m]

[m]\frac{2^{x-y}}{3^{x-y}}=\frac{8}{27}[/m]

[m](\frac{2}{3})^{x-y}=(\frac{2}{3})^{3}[/m]

[b]x-y=3[/b]