f(x) = lncosx, f'(x) = -tg(x) g(x) = x, g'(x) = 1 lim_(x → 0) f(x)/g(x) = lim_(x → 0) f'(x)/g'(x) = lim_(x → 0) -tgx = -tg(0) = 0 Ответ 0