|z|=√x2+y2
z=1–4i
|z|=√12+(–4)2=√17
|z|2=17
2.
i2=–1
i3=–i
i4=1
i32=(i4)8=18=1
i29=i28·i=(i4)7·i=17·i=i
[m]z=\frac{4i^{2}-5i^{32}}{-5-3i^{29}}=\frac{4\cdot (-1)-5\cdot 1}{-5-3i}=\frac{-9}{-5-3i}=\frac{9}{5+3i}[/m]
[m]\frac{9}{5+3i}=\frac{9\cdot (5-3i)}{(5+3i)(5-3i)}=\frac{9\cdot (5-3i)}{5^2-(3i)^2}=\frac{9\cdot (5-3i)}{25+9}=\frac{9\cdot (5-3i)}{34}[/m]
z=[m]\frac{9\cdot (5+3i)}{34}=\frac{45+27i}{34}=\frac{45}{34}+\frac{27}{34}i[/m]
Re z=[m]\frac{45}{34}=[/m]
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