Пусть f(x) = x² – 3. Найти f(1 – √3) + f (1 + √3).
f(1–√3)=(1–√3)2–3=1–2√3+3–3=1–2√3 f(1+√3)=(1+√3)2–3=1+2√3+3–3=1+2√3 f(1–√3)+f(1+√3)=1–2√3+1+2√3=2 О т в е т. 2