Задача 37252 ...
Условие
математика ВУЗ
1012
Все решения
du=(1+lnx)`dx=dx/x
∫ sqrt(u)du= ∫ u^(1/2)du=u^(3/2)/(3/2)+C=(2/3)sqrt(u^3)+C=
= [b](2/3)sqrt((1+lnx)^3)+C[/b]
du=(1+lnx)`dx=dx/x
∫ sqrt(u)du= ∫ u^(1/2)du=u^(3/2)/(3/2)+C=(2/3)sqrt(u^3)+C=
= [b](2/3)sqrt((1+lnx)^3)+C[/b]