(x+1)dx=d(x^2+2x+1)/2
∫ ^(1)_(0)(x+1)dx/(x^2+2x+1)= ∫ ^(1)_(0)(d(x^2+2x+1)/2)/(x^2+2x+1)=
=(1/2)ln|x^2+2x+1|^(1)_(0)=
=(1/2)(ln4-ln1)=(1/2)ln2^2=2*(1/2)ln2= [b]ln2[/b]
d(x-2)=dx
∫ ^(3)_(2)sqrt(x-2)dx= ∫ ^(3)_(2)sqrt(x-2)d(x-2)=
=(x-2)^(3/2)/(3/2)|^(3)_(2)=
=(2/3)* [b]([/b](3-2)^3/2-(2-2)^(3/2) [b])[/b]=
=(2/3)*(1-0)= [b](2/3)[/b]