dv=dx ⇒ v=x
=(x*ln(1+x^2))|^(1)_(0) - ∫ ^(1)_(0)х*(2xdx/(1+x^2))=
=(x*ln(1+x^2))|^(1)_(0) - 2 ∫ ^(1)_(0)(x^2+1-1)dx/(1+x^2))=
=(x*ln(1+x^2))|^(1)_(0) - 2 *(∫ ^(1)_(0)(x^2+1)dx/(1+x^2))+2∫ ^(1)_(0)dx/(1+x^2)=
=(x*ln(1+x^2))|^(1)_(0) -2*(x)|^(1)_(0)+(2arctg(x))|^(1)_(0)=
...