= ∫ ^(π/2)_(0)(1+cos2x)dx/2=(1/2)*(x+(1/2)sin2x)|^(π/2)_(0)=
=(1/2)*(π/2)+(1/4)sin(2*(π/2))+0=
= [b]π/4[/b]
2.
=(1/4) ∫ ^(3)_(2)dx/(x^2-0,25)=
=(1/4)*(1/0,5)ln|(x-0,5)/(x+0,5)|^(3)_(2)=
=0,5ln|(3-0,5)/(2-0,5)|-0,5ln|(2-0,5)/(1-0,5)|=
=0,5ln|7/3|-0,5ln|3|= [b]0,5ln(7/6)[/b]