=переходим к полярным координатам
x=rcos φ ; y=rsin φ
dxdy=rdrd φ
= 2∫ ^(π)_(0) ∫ ^(2)_(0)(2-rsin φ )rdrd φ =
=2 ∫ ^(π)_(0) ∫ ^(2)_(0)((2r-r^2sin φ )dr)d φ =
=2∫ ^(π)_(0)((2r^2/2)-(r^3/3)sin φ )|^(2)_(0)d φ =
=2∫ ^(π)_(0)(4-(8/3)sin φ )d φ =
=2*(4φ +(8/3)cos φ )|^(π)_(0)=8π+(16/3)(cosπ-cos0)=
[b]=8π-(32/3)[/b]