(1/3b)–(1/a)=(a–3b)/(3ba)
(a–3b)·(a+3b)/(3ab) : (a–3b)/(3ba)=
= ((a–3b)·(a+3b)/(3ab) )· ((3ba)/(a–3b) )=
= ((a–3b)·(a+3b)·(3ba) ) / ((3ab)·(a–3b) )=
=a+3b
при a= 3 целых (1/7) b=5 целых 2/7
3 целых 1/7+3·( 5 целых 2/7)= (22/7) + 3·(37/7)=
=(22/7)+(111/7)=133/7= 19