ln(x+sqrt(1+x^2))dx
Интегрируем по частям: ln(x+sqrt(1+x^2))=u dx=dv du=dx/sqrt(1+x^2) v=x ∫ ln(x+sqrt(1+x^2)dx=x*ln(x+sqrt(1+x^2)) - ∫ xdx/sqrt(1+x^2)= =x*ln(x+sqrt(1+x^2)) -(1/2)*2sqrt(1+x^2) + C= = [b]x*ln(x+sqrt(1+x^2)) -sqrt(1+x^2) +C[/b]