√5x+2y=v
{u+v=34
{u·v=273
{u=34–v
{(34–v)·v=273
v2–34v+273=0
D=64
v1=(34–8)/2=13; v2=(34+8)/2=21
u1=34–13=21; u2=13
Обратный переход
√5x–2y=21
5x–2y=441
5x+2y=169
10x=610
x=61
y=–68
5x–2y=169
5x+2y=441
x=61
y=68
О т в е т. (61;–68);(61;68)