vector{CA}=(1-(-3);1-(-2);5-5)=(4;3;0)
vector{CB}=(1-(-2);1-0;5-7)=(3;1;-2)
|vector{CA}|=sqrt(4^2+3^2+0^2)=5
|vector{CB}|=sqrt(3^2+1^2+(-2)^2)=sqrt(14)
Найдем скалярное произведение векторов:
vector{CA}*vector{CB}=4*3+3*1+0*(-2)=15
сos ∠ ACB=(vector{CA}*vector{CB})/|vector{CA}|*|vector{CB}|=
=15/(5*sqrt(14))=3sqrt(14)/14
∠ ACB=arccos(3sqrt(14)/14)