Задача 32868 ...

sova

2019-01-21 12:27:12

★

S= ∫^(ln3)_(ln2) (e^(3x)-e^(x))dx=((1/3)e^(3x)-e(x))|^(ln3)_(ln2)=

=(1/3)e^(3ln3)-e^(ln3)-(1/3)e^(3ln2)+e^(ln2)=

=(1/3)(e^(ln3))^3-3-(1/3)(e^(ln2))^3+2=

=(1/3)*3^3-(1/3)*2^3-1=

=(19/3)-1=16/3