y=x, y=1/2 x,y=-1/2 x^2+2x.
=∫^(2)_(0)(x-(1/2)x)dx+ ∫ ^(3)_(2)((-1/2)x^2+2x-(1/2)x)dx=
= (1/2)*(x^2/2)|^(2)_(0) +((-1/2)*(x^3/3)+(3/2)*(x^2/2))|^(3)_(2)=
=1 - 0 + (-1/2)*9+(3/4)*(9) - (-1/2)*(8/3)-(3/4)*4=
=1 - (9/2)+ (27/4) + (4/3) -3=