Задача 32349 (3-2i)*(7-i)...

eac201

2018-12-23 16:49:00

(3-2i)*(7-i)

marat2014

2018-12-23 16:55:17

(3-2i)(7-i)=0
21-3i-14i+2i^(2)=0
2i^(2)-17i+21=0
Найдем корни i
D=(-17)^(2)-4*2*21=289-168=121
i1=(17+ sqrt(121))/4=7
i2=17- sqrt(121)/4=1.5
Ответ: i1=7 , i2=1.5