Найдите [m] f \left( \frac{\pi}{9} \right) [/m], если [m] f(x) = - \frac{1}{3} \text{tg} \ 3x [/m] Выберите ответ: ○ – [m]\frac{1}{2}[/m] ○ –4 ○ 2 ○ [m]\frac{1}{4}[/m] ○ – [m]\frac{1}{4}[/m]
f `(x)=(–1/3)·(tg3x)`=(–1/3)·(1/cos23x)·(3x)`=–1/cos23x f`(π/9)=–1/cos2(π/3)=–4