Найдите [m] f \left( \frac{\pi}{9} \right) [/m], если [m] f(x) = - \frac{1}{3} \text{tg} \ 3x [/m] Выберите ответ: ○ - [m]\frac{1}{2}[/m] ○ -4 ○ 2 ○ [m]\frac{1}{4}[/m] ○ - [m]\frac{1}{4}[/m]
f `(x)=(-1/3)*(tg3x)`=(-1/3)*(1/cos^23x)*(3x)`=-1/cos^23x f`(π/9)=-1/cos^2(π/3)=-4