Задача 31660 ...
Условие
математика ВУЗ
399
Решение
★
x^2=u
2xdx=du
xdx=(1/2)du
= (1/2)*∫ 6^(u)du= (1/2)*(6^(u)/ln6) + C=
=(1/(2ln6))*6^(x^2)+ C
x^2=u
2xdx=du
xdx=(1/2)du
= (1/2)*∫ 6^(u)du= (1/2)*(6^(u)/ln6) + C=
=(1/(2ln6))*6^(x^2)+ C