Задача 31490 5. y = 2^(x^2), x_0 = 1....

sanchoys2310

2018-12-02 16:16:15

5. y = 2^(x^2), x_0 = 1.

sova

2018-12-02 16:35:37

★

y`=2^(x^2)*(x^2)`*ln2
y`=2^(x^2)*(2x)*ln2
y`=ln2*2^(x^2+1)*x

y`(1)=ln2*(2^(1+1))*1
y`(1)=4ln2