а) log9(3^(2x)+5sqrt(2)sinx-6cos^2x-2) = x б) [-2Pi; -Pi/2] [block] а) ((x-2)^2)/(2) + (18)/((x-2)^2) = 7((x-2)/(2) - (3)/(x-2))+10 [/block] б) [-2; 2]