Задача 31274 log(16)4 - log48 = ... log3x +...

vk152085396

2018-11-25 16:46:41

log(16)4 - log48 = ...

log3x + log(sqrt(3))x + log(1/3)x = 6

sova

2018-11-25 17:25:48

log_(16)4-log_(1/4)8=log_(2^4)2^2-log_(2^(-2))2^(3)=

=(2/4)log_(2)2+(3/2)log_(2)2=(1/2)*1+(3/2)*1=2


log_(3)x+log_(3^(1/2))x+log_(3^(-1))x=6

log_(3)x+(1/(1/2))log_(3)x-log_(3)x=6
2log_(3)x=6
log_(3)x=3
x=27