4^(log_(5)3+log_(2)3)=4^(log_(5)3)*4^(log_(2)3)=4^(log_(5)3)*(2^2)^(log_(2)3)=4^(log_(5)3)*2^(log_(2)3^2)=4^(log_(5)3)*(3^2)=
=9*4^(log_(5)3)
3^(log_(5)4)=4^(log_(5)3)
От первой дроби останется 3/9=1/3
25^(log_(5)(2+(1/sqrt(3))))=5^(2log_(5)(2+(1/sqrt(3))))=
=5^(log_(5)(2+(1/sqrt(3)))^2)=(2+(1/sqrt(3)))^2
2^(log_(sqrt(2))(2-(1/sqrt(3))))=(sqrt(2))^(2log_(sqrt(2))(2-(1/sqrt(3))))=
=(sqrt(2))^(log_(sqrt(2))(2-(1/sqrt(3)))^2)=(2-(1/sqrt(3)))^2
О т в е т. (1/3)+(2+(1/sqrt(3)))^2+(2-(1/sqrt(3)))^2=
=(1/3)+4+(1/3)+2*2*(1/sqrt(3)) + 4 +(1/3)-2*2*(1/sqrt(3))=9