Задача 30502 (6+2i)-(-3-4i) (2-3i)-(1-2i) (3-2i)*(-1-i) ......

vk152085396

2018-10-24 19:13:57

(6+2i)-(-3-4i)
(2-3i)-(1-2i)
(3-2i)*(-1-i)
...

sova

2018-10-24 19:22:34

(6+2i)-(-3-4i)=6+2i+3+4i=(6+3)+(2i+4i)=9+6i
(2-3i)-(1-2i)=2-3i-1+2i=(2-1)+(2i-3i)=1-i
(3-2i)*(-1-i)=3*(-1)-2i*3+3*(-i)-2i*(-i)=-3-6i-3i+2i^2=-3-6i-3i-2=-5-9i
(3-2i)*(2-i)*(1+4i)=(3*2-2i*2+3*(-i)-2i*(-i))*(1+4i)= (6-4i-3i-2)*(1+4i)=
=(4-7i)*(1+4i)=4*1-7i*1+4*4i-7i*(4i)=4-7i+16i-28i^2=4-7i+16i+28=
=32+9i