Задача 30038 ...

vk279864062

2018-10-07 19:40:27

∫cos^2*6x dx

sova

2018-10-07 20:52:51

cos^26x=(1+cos12x)/2

∫cos^26x dx= ∫ (1+cos12x)dx/2=(1/2) ∫ dx + (1/2) ∫ cos12xdx=

=(1/2)*x +(1/2)*(1/12) ∫ cos12xd(12x)=

=(1/2)*x+(1/24)sin12x +С

О т в е т. (1/2)*x+(1/24)sin12x +С