Помогите с высшей математикой
∛х=t
x=t^3
∛x^2=(∛x)^2=(t)^2
dx=(t^3)`dt=3t^2dx
∫ dx/(∛(x^2)*(∛x + 1)^3=∫3t^2dt/(t^2*(t+1)^3)=
=3 ∫ dt/(t+1)^3 =3* ∫ (t+1)^(-3)d(t+1)=
=3*(t+1)^(-2)/(-2)+C=
=-3/(2*(t+1)^2)+C=
=-(3/2)*(1/(∛x+1)^2)+C