интеграл 1/(5-x^(2/3))
∫ dx/(5–x^(2/3)) Замена переменной x^(2/3)= t^2 x^2=t^6 x=t^3 dx=3t^2dt ∫ dx/(5–x^(2/3)) = ∫ 3t^2dt/(5-t^2)= =-3 ∫ ((5-t^2)-5)dt/(5-t^2)= = - 3 ∫ dt+15 ∫ dt/(5-t^2) = - 3t - - (15/2sqrt(5))ln|(t-sqrt(5))/(t+sqrt(5))| + C, t=∛x