Пусть
d_(1)=3x; d_(2)=5x
a^2=(d_(1)/2)^2+(d_(2)/2)^2
Р=4а ⇒ 136 = 4а ⇒ а= 34
34^2=(3x/2)^2+(5x/2)^2
1156 = (9x^2/4) + (25x^2/4)
1156 = 34x^2/4
x^2=34*4
x=2sqrt(34)
S ( ромба) = (1/2)d_(1)*d_(2) = (1/2) *3x * 5x = 15x^2/2 =
=1020
S(ромба) = a*h ⇒ h=S/a=1020/34= 30