Все на картинке
(3^(3*(2x-3)))^(1/3) > (3^4*(6-4x)/(x+1))^(1/2) 3^(2x-3) > 3 ^ ((12-8x)/(x+1)) ⇒ 2x-3 > (12-8x)/(x+1) ((2x-3)(x+1)-(12-8x))/(x+1) > 0 (2x^2+7x-15)/(x+1) > 0 D=49+120=169 (2x-3)(x+5)/(x+1) > 0 _-__ (-5) __+__ (-1) _-__ (3/2) _+_ О т в е т. (-5;-1) U ( 3/2;+ бесконечность )