Вычислите косинус угла между прямыми АВ и СD если: А (7; –8;15), В (8; –7; 13), С (2; –3; 5) D(–1; 0; 4)
AB·CD = |AB| · |CD| · cos a AB=( 8–7; –7+8; 13–15 ) = (1; 1; –2) CD=(–1–2; 0+3; 4–5) = (–3; 3; –1) AB·CD = 1·(–3) + 1·(3) + (–2)·(–1) = –3 + 3 + 2 = 2 |AB| = √12 + 12 + (–2)2 = √6 |CD| = √9 + 9 + 1 = √19 2 = √114 · cos a cos a = 2/√114