Sin 2x+√3sinx=0 [5pi/2; 7pi/2]
2 sinx cosx + √3sinx=0 sinx (2cosx+√3)=0 1)sin x=0 x=Пn 2)2cosx+√3=0 cosx=-√3/2 x=+-5П/6+2Пn ОТБОР КОРНЕЙ x=3п-п/6=17п/6 х=5п/2+п/2=3п х=3п+п/6=19п/6