2sin^2x+4=3корень из 3
sin^2x=(1-cos2x)/2 2*(1-cos2x)/2 + 4 = 3sqrt(3) cos2x=5-3sqrt(3) 2x=± arccos(5-3sqrt(3))+2πk, k∈Z x=± (1/2)arccos(5-3sqrt(3))+πk, k∈Z x=± (1/2)*(π-arccos(3sqrt(3)-5))+πk, k∈Z О т в е т. x=± (1/2)*(π-arccos(3sqrt(3)-5))+πk, k∈Z