Сократите дробь (1+4x–4y)/(4y2–4x2–y–x)
4y2–4x2–y–x=4·(y2–x2)–(y+x)= =4·(y–x)·(y+x)–(y+x)= =(y+x)·(4y–4x–1) (1+4x–4y)/(4y2–4x2–y–x)= =(1+4x–4y)/((y+x)·(4y–4x–1))= =–(4y–4x–1)/((y+x)·(4y–4x–1))=–1/(y+x)