Номер 6
b1 = –5 b_(n+1) = –2*(1/b_(n)) При n=1 b_(2)=b_(1+1) = –2*(1/b_(1)) = –2*(1/(–5)) = 2/5 При n=2 b_(3) =b_(2+1)= –2*(1/b_(2)) = –2*(1/(2/5)) = -2*(5/2)=-5 При n=3 b_(4) = –2*(1/b_(3)) = –2(1/(–5)) = 2/5 и т.д.