Последовательность bn задана условиями b1 = –5, bn+1 = –2 1/bn Найти b2
b1 = –5 bn+1 = –2·(1/bn) При n=1 b2=b1+1 = –2·(1/b1) = –2·(1/(–5)) = 2/5 При n=2 b3 =b2+1= –2·(1/b2) = –2·(1/(2/5)) = –2·(5/2)=–5 При n=3 b4 = –2·(1/b3) = –2(1/(–5)) = 2/5 и т.д.