(3x)^3*x^-9/x-10*2x^5
((3x)^3·x^(–9))/(x^(–10)·2x^5)= =(3^3*x^3*x^(-9))/(x^(–10)·2x^5)= =(27/2)x^(3-9-(-10)-5)=13,5x^(-1)=13,5/x