sin8x-sin4x=cos6x
sin8x–sin4x=cos6x; 2sin2x*cos6x=cos6x; cos6x*(2sin2x-1)=0 cos6x=0 или sin2x=1/2 6x= (π/2)+πk, k∈Z или 2x=(π/6)+2πn, n∈Z или 2х=(5π/6)+2πm, m∈Z О т в е т. (π/12)+(π/6)k, (π/12)+πn, (5π/12)+πm, k, n, m∈Z