Решить неравенство:
x2–12x+35=(x–7)·(x–5) x2–17x+70=(x–7)·(x–10) (2/(х–7)(х–5))+(3/(х–7)(х–10)) ≤ 0; (2·(х–10)+3·(х–5))/((х–5)·(х–7)·(х–10)) ≤ 0; (5·(х–7))/((х–5)·(х–7)·(х–10)) ≤ 0; ____+___ (5) ___–__ (7) __–___ (10) __+__ х∈(5;7)U(7;10) Ответ: (5;7)U(7;10)