sin268 °–sin238 °–(1/2)·sin 106 °+3.
sin238 °=(1–cos76 °)/2.
sin268 °–sin238 °–(1/2)·sin 106 °+3=
=(1–cos136 °)/2– (1–cos76 °)/2–(1/2)·sin 106 °+3=
=(1/2)·(cos76 °–cos136 °)–(1/2)·sin 106 °+3=
=sin106 ° · sin30 °–(1/2)·sin 106 °+3=
=(1/2)·sin 106 °–(1/2)·sin 106 °+3=3
Ответ: 3