Задача 11180 f(x)=(x^2-9)/(x+3) f(-2)-? f(1/3)-? f(1)-?...

vk263992005

02.11.2016

f(x)=(x^2-9)/(x+3)

f(-2)-?
f(1/3)-?
f(1)-?

SOVA

02.11.2016

★

x^2-9=(x-3)(x+3)
F(x)=x-3
F(2)=2-3=-1
F(1/3)=(1/3)-3=-2 целых 2/3
F(1)=1-3=-2