Решите уравнение 5^(log(25)(4x-7)) = 11
5^(log(25)(4x-7)) = 11 5^(log(5^2)(4x-7)) = 11 5^((1/2)log(5)(4x-7)) = 11 5^(log(5)(4x-7)^(1/2)) = 11 (4x-7)^(1/2) = 11 sqrt(4x-7) = 11 Возведем обе части квадрат 4x-7 = 121 4x = 121+7 x = 128/4 = 32 Ответ: 32