[b]Написать три первых и a_(n+1) член ряда a_n = 5n+3/(n+1)![/b]
a_(1)=(5*1+3)(1+1)!=8/2!=8/(1*2)=4, a_(2)=(5*2+3)/(2+1)!=13/3!=13/(1*2*3)=13/6, a_(3)=(5*3+3)/(3+1)!=18/4!=18/(1*2*3*4)=3/4, a_(n+1)=(5*(n+1)+3)/(n+1+1)!=(5n+8)/(n+2)!