f(x) = 3√2 sin(x) - 2√2 cos(x) в точке с абсциссой, равной x₀ = π/4
f(x)=3sqrt(2)sinx-2sqrt(2)cosx,
f'(x)=3sqrt(2)cosx+2sqrt(2)sinx,
k=f'(x_(0))=f'(π/4)=3sqrt(2)*cos(π/4)+2sqrt(2)*sin(π/4)=
=3sqrt(2)*(sqrt(2))/2+2sqrt(2)*(sqrt(2))/2=3+2=5.