y=2(−4arcctgx)
Найдите y''(x).
В ответ введите значение y''(1).
[m]y'(x)=-8 \cdot \frac{-1}{1+x^2} = 8 \cdot \frac{1}{1+x^2}[/m]
[m]y''(x) = 8 \cdot \frac{1'(1+x^2) - 1(1+x^2)'}{(1+x^2)^2} = 8 \cdot \frac{0- 2x}{(1+x^2)^2} =-\frac{16x}{(1+x^2)^2}[/m]
[m]y''(1) = -\frac{16 \cdot 1}{(1+1^2)^2} = -\frac{16}{2^2} = -4[/m]