Перевести функцию y=(3x+2)/(x+1) в y=k/(x+a) +b
y = (3x+2)/(x+1) = (3x+3-1)/(x+1) = (3(x+1) - 1)/(x+1) = -1/(x+1) + 3 k = -1; a = 1; b = 3