найдите log_(a)(b^(2)a^(3)), если log_(b) a = 1/2
[m]log_{b}(a) = \frac{1}{2}[/m] [m]\log_{a}(b^2a^3) = \log_{a}(b^2) + \log_{a}(a^3) = \log_{a}(b^2)+3 = 2\log_{a}(b)+3[/m] Если [m]log_{b}(a) = \frac{1}{2}[/m], то [m]log_{a}(b) = 2[/m] Поэтому: [m]\log_{a}(b^2a^3) = 2\log_{a}(b)+3 = 2 \cdot 2 + 3 = 7[/m]