Найдите значение выражения: Отвуты:sqrt( 3)/3, 1/2, sqrt( 3), sqrt( 3)/6
[m]\frac{1 - tg^2(\pi/6)}{4tg(\pi/6)} = \frac{1 - (1/\sqrt{3})^2}{4(1/\sqrt{3})} = \frac{1-3/9}{4/\sqrt{3}} = \frac{2}{3} : \frac{4}{\sqrt{3}} = \frac{2}{3} \cdot \frac{\sqrt{3}}{4} = \frac{\sqrt{3}}{6}[/m]
