Задача 75631 ...

632f635587d19127bff140f0

1/31/2024 7:45:34 PM

Найдите значение выражения sin (-11π/6) cos 19π/6 tg 5π/4 ctg (-5π/3) Ответы: sqrt(3)/2, 1/4, -1/4, sqrt(2)/2

626fab9a354ab65fb2f43abb

1/31/2024 8:07:34 PM

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sin (-11π/6) = sin (12π/6 - 11π/6) = sin π/6 = 1/2
cos (19π/6) = cos (18π/6 + π/6) = -cos π/6 = -sqrt(3)/2
tg (5π/4) = tg (π + π/4) = tg π/4 = sqrt(2)/2
ctg (-5π/3) = ctg (6π/3 - 5π/3) = ctg π/3 = sqrt(3)/3